Since the process P3 has 2 unit of burst time hence it will be given priority over others. At this time, the execution of process P3 is stopped and the process with the least remaining burst time is searched. The next process P3 arrives at time unit 2.Hence Process P2 is scheduled on the CPU according to the algorithm. The OS has executed P1 for one unit of time till now the remaining burst time of P1 is 7 units. Till now, there are two processes available in the ready queue. Since the algorithm we are using is SRTF which is a preemptive one, the current execution is stopped and the scheduler checks for the process with the least burst time. The next process arrives at time unit 1.This is the only available process in the list therefore it is scheduled. Since, at time 0, the only available process is P1 with CPU burst time 8.The Gantt chart is prepared according to the arrival and burst time given in the table. Their arrival time and burst time are given below in the table. In this Example, there are five jobs P1, P2, P3, P4, P5 and P6. This PCB is accessed on the next execution of this process. The context of the process is saved in the Process Control Block when the process is removed from the execution and the next process is scheduled. Once all the processes are available in the ready queue, No preemption will be done and the algorithm will work as SJF scheduling. At the arrival of every process, the short term scheduler schedules the process with the least remaining burst time among the list of available processes and the running process. In SRTF, the execution of the process can be stopped after certain amount of time. This Algorithm is the preemptive version of SJF scheduling. Next → ← prev Shortest Remaining Time First (SRTF) Scheduling Algorithm

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